# p2o5 molar mass

We need to find out how much P is in P2O5. Mass of P from the equation = 4x31 = 124g. O peso molecular e massa molar de P2O5 é 141,945. determine the molecular compound molar mass of P X 2. molar mass of O X 5. The guarantee is expressed as phosphate (P2O5). For bulk stoichiometric calculations, we are usually determining molar mass, which may also be called standard atomic weight or average atomic mass.If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. The relative molecular mass of phosphorous is 31 and of oxygen is 16. mass of 1 mol of P2O5 =(31x2)+(16x5) And this is indeed the case. % / molar mass. 98.25 g/mol 108.0 g/mol 219.9 g/mol O 141.9 g/mol 46.97 g/mol Get more help from Chegg Get 1:1 help now from expert Chemistry tutors The next step shows you that P2O5 is 43.7% P. Atomic weight: P = 31 O = 16 P 2: two of them so 2 X 31 = 62g O 5: five of them so 5 X 16 = 80g Total weight for P 2 O 5 142g The proportion of P in P 2 O 5 is [62 / 142] = 0.437 Now we can calculate elemental P. That is why it is called phosphorus anhydride at times. That's half of the molar mass of 283.89, so the molecular formula must be an exact doubling of the empirical formula, thus P4O10. molar mass of P2O5 = 142 g/mol Noe we will find the moles of 0.560 g P2O5: moles = mass / molar mass moles = 0.560 g / 142 g/mol moles = 0.0039 mol now we will find the atoms present in 0.0039 moles: 0.0039 * 6.02 * 10∧ 23 molecules 2.357 * 10∧ 21 molecules P2O5 consist of 7 atoms: 2.357 * 10∧ 21 * 7 = 16.499 * 10∧ 21 atoms No of moles=given mass÷molar mass 0.0250=given mass÷31×2+16×5 Given mass=142×0.025 Hence mass of 0.025 moles of P2O5 is 3.55g Now we can obtain the theoretical yield of P2O5 as follows: 4P + 5O2 → 2P2O5. we use molar masses to find the mass of P2O5 that would have produced MgNH4PO4 x 6H20(s. it takes 1 P2O5 to have enough P's to make 2 MgNH4PO4 x 6H20. Molar Mass of P2O5 = (31x2) + (16x5) = 62 + 80 = 142g/mol. Molar Mass of P = 31g/mol. P2O5, which has a molecular mass of 141.9, can usually be found as its dimeric, P4O10. = 141.94. From the equation, 124g of P produced 284g of P2O5. 8.311 g. @ (141.95 g/mol P2O5) / (482.80 grams for 2 moles MgNH4PO4*6H2O) = 2.4436 g P2O5. So in your formula of P2O5, the total mass is 2 x 31 + 5 x 16 = 142 (I've rounded off). Mass of P2O5 from the equation = 2 x 142 = 284g. 1 mole of P2O5 whose molar mass is 141.95 g/mol, with its 2 P's. The molecular mass of P is 30.97, and that of O is 16. What is the molar mass of P2O5? Phosphorous acid is H3PO3. P2O5 is Phosphorous pentoxide. its experimental molar mass is 284 g/mol. so. See the link below. so . 1.000 g of MgNH4PO4*6H20 @ (1 molar mass of P2O5) / ( 2 molar masses of MgNH4PO4*6H20) = 1.000 g MgNH4PO4*6H20 @ (141.9 g/molP2O5) / (2)(245.41 g/mol MgNH4PO4*6H20) = 0.2891 grams of P2O5 P2O5's reaction with water causes the … 284 / 141.94 = a) for the mass of "p2O5" in the initial mass of fertilizer analyzed. produces 2 molar masses of MgNH4PO4*6H2O , whose molar mass is 241.40 g/mol. take smallest and / answers the empirical formula for a compound is P2O5. It reacts powerfully with water to form ortophosphoric acid, H3PO4. Linear Formula P 2 O 5. 4P + 5O2 → 2P2O5 ( 141.95 g/mol, with its 2 P 's P is in P2O5 compound! Empirical formula for a compound is P2O5 = 284g X 142 = 284g 80 =.. We need to find out how much P is in P2O5 142 = 284g the. Need to find out how much P is in P2O5 482.80 grams for 2 moles *... 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